tlippy
New member
Are we running 4000 or 5000 RPM most of the time? The black bars cover 0-4000. I'm thinking that we're doing 5000.
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What RPM are we runnung?
- Thread starter tlippy
- Start date
Snowdog
New member
Depends on how fast you are going and whether you are going up or down.
grey.hound
New member
http://www.bmw-scooters.com/forum/c600-c650gt-technical/582-technical-manual-bmw-university.html
First thread has a link to the pdf.
The pdf might have the answer you are lookng for; there is a nice graph on page 15 of the manual.
Here is what it says:
The centrifugal clutch begins to activate
at approx. 2,200 rpm and is fully closed from
approx. 4,200 rpm on. Under full throttle
acceleration, the lowest transmission ratio will
automatically be maintained until a speed of
about 31 mph is reached, with the engine
speed increasing to approx. 5,800 rpm. In parallel
to the increase of the engine speed, the centrifugal
force increases continuously at the rollertype
weights of the input shaft, which are braced
against the ramp plate and exert a precisely
calculated adjustment force on the movable disc.
In order to optimally capitalize the available
power and thus achieve maximum dynamism
and efficiency of the powertrain, the roller-type
weights were designed so that the CVT ratio lies
as close as possible to the engine speed range
where the maximum engine torque (49 ft./lbs. @
6,000 rpm) is delivered.
From an engine speed of 5,800 rpm on, the
adjustment force is high enough to compress
the discs against the tractive force of the drive
belt and to force the drive belt onto a larger cone
diameter. The spring rate of the pressure spring
on the driven shaft end is tuned to where the
discs are forced apart by the tractive force of the
drive belt to thus continuously vary the transmission
ratio to “fast” with increasing centrifugal
force on the rollers.
The engine speed will remain nearly constant
between approx. 31 and 68 mph and the
transmission ratio will change during this
phase from the lowest ratio of 2.41 : 1 to the
maximum ratio of 1.0 : 1, dependent on the
speed of the vehicle. No further adjustment will
take place from a speed of 68 mph on and the
increase of the road speed up to top speed is
realized exclusively by raising the engine speed.
Whenever the vehicle is decelerated or the rider
backs off the throttle, the process will be reversed.
The engine speed and thus the centrifugal
force on the roller-type weights decreases, the
tractive force of the belt drops and the pressure
spring in the driven shaft will compress the
discs. The drive belt will thus force the discs on
the driven shaft apart and the transmission ratio
will be reduced. The shoes of the centrifugal
clutch will automatically disengage from the
clutch drum and the power between input and
output shaft is interrupted.
First thread has a link to the pdf.
The pdf might have the answer you are lookng for; there is a nice graph on page 15 of the manual.
Here is what it says:
The centrifugal clutch begins to activate
at approx. 2,200 rpm and is fully closed from
approx. 4,200 rpm on. Under full throttle
acceleration, the lowest transmission ratio will
automatically be maintained until a speed of
about 31 mph is reached, with the engine
speed increasing to approx. 5,800 rpm. In parallel
to the increase of the engine speed, the centrifugal
force increases continuously at the rollertype
weights of the input shaft, which are braced
against the ramp plate and exert a precisely
calculated adjustment force on the movable disc.
In order to optimally capitalize the available
power and thus achieve maximum dynamism
and efficiency of the powertrain, the roller-type
weights were designed so that the CVT ratio lies
as close as possible to the engine speed range
where the maximum engine torque (49 ft./lbs. @
6,000 rpm) is delivered.
From an engine speed of 5,800 rpm on, the
adjustment force is high enough to compress
the discs against the tractive force of the drive
belt and to force the drive belt onto a larger cone
diameter. The spring rate of the pressure spring
on the driven shaft end is tuned to where the
discs are forced apart by the tractive force of the
drive belt to thus continuously vary the transmission
ratio to “fast” with increasing centrifugal
force on the rollers.
The engine speed will remain nearly constant
between approx. 31 and 68 mph and the
transmission ratio will change during this
phase from the lowest ratio of 2.41 : 1 to the
maximum ratio of 1.0 : 1, dependent on the
speed of the vehicle. No further adjustment will
take place from a speed of 68 mph on and the
increase of the road speed up to top speed is
realized exclusively by raising the engine speed.
Whenever the vehicle is decelerated or the rider
backs off the throttle, the process will be reversed.
The engine speed and thus the centrifugal
force on the roller-type weights decreases, the
tractive force of the belt drops and the pressure
spring in the driven shaft will compress the
discs. The drive belt will thus force the discs on
the driven shaft apart and the transmission ratio
will be reduced. The shoes of the centrifugal
clutch will automatically disengage from the
clutch drum and the power between input and
output shaft is interrupted.
- Thread starter
- #4
tlippy
New member
Thanks Greyhound for an informative and adult reply
TwoPort
Member
Oh yes, I totally understand. But is the bike actually moving during all of this?
grey.hound
New member
Yeah, I didn't write that. cut and paste.
Pigpenracing
New member
Who cares.... You can run it at redline all day and not hurt it.
Snowdog
New member
Then I was right.